how many of .12M KOH must be added to 60 ml of 0.2M HF to produce a solution with a pH 3.3(pKa of HF is 3.3)...answer is 5 ml...but don't understand how they got the answer.
There's a miscalc in the solution if you look it over again. As it's written:
(.20)(60) = 1.20, which is not correct. It should read (.20)(60) = 12, with V2 = 100 mL (not 10 mL as is listed). The answer then would be 50 mL as opposed to 5 mL. In order for the answer to be 5 mL you would need only 6 mL of .20 M HF. Hope this helps.