Sound waves in tubes

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golgiapparatus88

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Hey everyone. I'm getting more and more confused on soundwaves as I keep studying. Here is my understanding...

Tube with both ends open: both ends will be nodes and will act just like a regular transverse wave with fn=nv/2L and wavelength=2L/n

Tube with 1 end up: the OPEN end will be the node and the closed end will be antinode. fn=nv/4L and wavelength = 4L/n where n=1,3,5...

I really hope that's right but here is why I have confusion. Every picture I look at contradicts the previous (unless I'm missing something). Here's what I mean...

http://www.ling.upenn.edu/courses/Fall_1997/ling520/qualitative_formants/StandingWave.png

http://hep.physics.indiana.edu/~rickv/Standing_Sound_Waves.html

HELP! 🙂
 
I just looked up my physics text book and it clearly stated that the opened end and the closed end of a pipe are an antinode and a node respectively. So, I am a bit skeptical with the information given from the link.
Closed pipe (1 end opens, 1 end closes): f = nv/4L (n = 1,3,5, ...)
Opened pipe (both end opens) : f = nv/2L (n = 1,2,3, ...)

You might want to consult with others (or reliable textbooks) on this.
 

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