TPR, Physics #54, kinematics

[riseNshine]

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Hi guys, question is as follows:
One second after being thrown straight down, an object is traveling at a speed of 20 m/s. How fast will it be traveling two seconds later? (Ignore air resistance).

Answer is 40 m/s. I had some difficulty because if you use the equation v=v(0)+at,then one second after, that would mean 20=0+10(1) and 20 does not equal 10. If it's being thrown straight down,doesn't v(0)=0, so 20 wouldn't equal 10?

^The above confused me,but you can still solve the problem without that info, I just wanted to clarify whether my line of thinking was flawed.

Answer for those wondering:
change in v=10(2) so new speed is: v=20+20.

 

[akim6890]

You're assuming that the ball is being dropped and not thrown. It has an initial velocity of 10 m/s.

 

[Qester]

If you look at it as v= vi +at, the question puts vi=20

v= 20 +10(2)
v=40

The information prior to the initial velocity of 20m/s is just a distraction.