- Joined
- Jul 30, 2009
- Messages
- 76
- Reaction score
- 1
I don't exactly understand how Potassium Phosphate dissociates into 4 particles. Here is the question.
Which of the following would be expected to exhibit the highest change in colligative properties of a dilute solution, given equal concentrations of each.
A. Glucose--only solvates and doesn't dissociate so only one particle
B. Sodium Chloride--dissociates into two particles
C. Potassium Phosphate--???
D. Sillver(II) iodide--dissociates into 3 particles
Princ. Rev. says that it dissociates into 4 particles, how is that?
But would the van't hoff factor only be 3 because there are only three ions in letter C. 2 K's and 1 PO4 minus 2 charge.....
Thanks in advance.
Which of the following would be expected to exhibit the highest change in colligative properties of a dilute solution, given equal concentrations of each.
A. Glucose--only solvates and doesn't dissociate so only one particle
B. Sodium Chloride--dissociates into two particles
C. Potassium Phosphate--???
D. Sillver(II) iodide--dissociates into 3 particles
Princ. Rev. says that it dissociates into 4 particles, how is that?
But would the van't hoff factor only be 3 because there are only three ions in letter C. 2 K's and 1 PO4 minus 2 charge.....
Thanks in advance.
