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do we need to know this equation for the real DAT:
log[A] = -kt/2.303
??
log[A] = -kt/2.303
??
what is log[A] = -kt/2.303 ? do we need to know this?
- Thread starter Smooth Operater
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hmmm, if i remember from ap chem, that should be the integrated rate law for 1st order reactions.
so if u were to look it up, look under "integrated rate laws" or "rate laws"
I've seen it more commonly written as ln([A]final/[A]initial)=-kt
[A] describes [A]final/[A]initial (where [A] is the concentration of a given reactant)
k describes the reaction rate constant. in this case, since its negative k, it is safe to assume that concentration decreased as time increases (hence the negative slope).
t=time elapsed
if you are given [A]final, [A] initial, and time elapsed, u should be able to find the constant k (rate reaction constant)
in regard to its prevalence on the DAT, i have no idea. im not even in college yet 😛.
someone correct me if im wrong. hope this helped a little 😀.
so if u were to look it up, look under "integrated rate laws" or "rate laws"
I've seen it more commonly written as ln([A]final/[A]initial)=-kt
[A] describes [A]final/[A]initial (where [A] is the concentration of a given reactant)
k describes the reaction rate constant. in this case, since its negative k, it is safe to assume that concentration decreased as time increases (hence the negative slope).
t=time elapsed
if you are given [A]final, [A] initial, and time elapsed, u should be able to find the constant k (rate reaction constant)
in regard to its prevalence on the DAT, i have no idea. im not even in college yet 😛.
someone correct me if im wrong. hope this helped a little 😀.
