Which direction does the induced current flow?

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johnwandering

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Question #4 in BR chapter 7.

It shows a system of a traveling rod inducing a current through a circuit. It asks which way is the induced current flowing?

-Clockwise?
-Counter-clockwise?

Isn't this a nonsensical question because there's 2 currents flowing in different directions?: 1.) The regular induced current flows one way, and 2.) the "Lenz's Law" induced current is flowing in the opposite direction in reaction to the rod's movement.

It asks for the "induced current," which apparently is NOT the Lenz's Law and is the normal electron flow according to the answer.
 
Induced current can be related to lenz's law. As the system is gaining X it has to compensate by gaining O (using their way- le shats principle of looking at it), since it's gaining O its inducing a current that is counterclockwise in direction. If it was gaining O then it would compensate by gaining X which would give a clockwise current.
 
Induced current can be related to lenz's law. As the system is gaining X it has to compensate by gaining O (using their way- le shats principle of looking at it), since it's gaining O its inducing a current that is counterclockwise in direction. If it was gaining O then it would compensate by gaining X which would give a clockwise current.

You're right and that makes this question a legitimate concern.

If something is moving through the field, there is an induction of an emf and the opposite emf.
If the question is asking about "which direction is the induced emf going?" it doesn't specify WHICH emf if being addressed. It could be one or the other.


I'm going to say this is a flawed and impossible question? Unless someone can help....
 
induced currents are normally made by entering/exiitng the field if I recall. But I applied lenz law which is what I was assuming they wanted and pretended it was entering the field, which in that case my theory holds.
 
Induced current can be related to lenz's law. As the system is gaining X it has to compensate by gaining O (using their way- le shats principle of looking at it), since it's gaining O its inducing a current that is counterclockwise in direction. If it was gaining O then it would compensate by gaining X which would give a clockwise current.



Whoaaa take a step back. This question is NOT asking about lenz's Law.
The system is gaining O, so (+) charges are being pushed Up-> counterclockwise direction. It's THAT simple. There is no "reaction" to gaining X because it's not gaining X. The bar is not entering a field, it's moving in a field already inundated with X.

The question is asking about induced CURRENT, not induced EMF, that's the confusion here.
The current is only flowing in one way. Even with Lenz's Law, the current flows one way.
 
Whoaaa take a step back. This question is NOT asking about lenz's Law.
The system is gaining O, so (+) charges are being pushed Up-> counterclockwise direction. It's THAT simple. There is no "reaction" to gaining X because it's not gaining X. The bar is not entering a field, it's moving in a field already inundated with X.

The question is asking about induced CURRENT, not induced EMF, that's the confusion here.
The current is only flowing in one way. Even with Lenz's Law, the current flows one way.


I'm so dumb. Yes it appears that it is correct.
I guess we have to be more aware of the distinction between induced current/induced emf.
 
Whoaaa take a step back. This question is NOT asking about lenz's Law.
The system is gaining O, so (+) charges are being pushed Up-> counterclockwise direction. It's THAT simple. There is no "reaction" to gaining X because it's not gaining X. The bar is not entering a field, it's moving in a field already inundated with X.

The question is asking about induced CURRENT, not induced EMF, that's the confusion here.
The current is only flowing in one way. Even with Lenz's Law, the current flows one way.

I contradicted myself, it wasn't even leaving/exiting so it could not induce one anyways zz.
 
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