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I've always wondered... and never really got a clear answer... on why pharmacy programs require calculus as a pre-req class? How does anything in calc relate to what a pharmacist will be doing?
Being able to understand calculus is what separate pharmacists from techs.
Huh, I thought it was the paycheck.
I would tend to agree with what most of the other posters here have already said. Although I think an even better question would be "why do so many pharmacy schools require Bio 2?"
I wonder the same thing. Why do future pharmacists need to know crap about plants, ecology, etc?
To answer some dumb random questions at the counsultation window.
Why is Cal a pharm pre-req? Because we need to calculate the limits of self-control before kicking a druggie out of the pharmacy.
I've always wondered... and never really got a clear answer... on why pharmacy programs require calculus as a pre-req class? How does anything in calc relate to what a pharmacist will be doing?
My calculus teacher told me, in regards to pharmacy specifically, the rate at which a drug is being released or broken down in your body or whatever you call it, is a function of some sort, forgot the specifics. I think along with organic they need a few hard pre reqs to show an applicant can handle tough coursework that's not just memorizing.
I wonder the same thing. Why do future pharmacists need to know crap about plants, ecology, etc?
Pharmacokinetics of every single drug used is measured by using calculus.
How do you use calculus to model zero-order kinetics? Maybe a better question would be, why would you use calculus?
I was gonna get really nerdy here, but I'll stop myself![]()
No, by all means, if you want to call me out, go ahead. I don't see calculus being used for this, but if you can enlighten me, please do.
Not necessarily a need, but just an optional thing. Did I make you mad or something? You did say you felt like I was calling you out on this.
dN/dt = -k
dN = -k dt
N = -k t + C
Which would give you a straight line with a negative slope.
N(0) = n0
n0 = -k (0) + C
n0 = C
N = -k t + n0
I know no one would really do this, but technically, you could use a little bit of calculus.