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The autoionization of water is an endothermic reaction
2H2O -> H3O+ + OH-
As the temperature of pure water increases the pH:
The given answer is decreases because [H+] increases, but I said it remains at 7 because [H+] equals [OH-] even after an equilibrium shift.
So the pH drops and so does the pOH? Why wouldn't the 2 cancel each other out?
2H2O -> H3O+ + OH-
As the temperature of pure water increases the pH:
The given answer is decreases because [H+] increases, but I said it remains at 7 because [H+] equals [OH-] even after an equilibrium shift.
So the pH drops and so does the pOH? Why wouldn't the 2 cancel each other out?