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The question is:
"Assuming that 2 ATP are consumed in moving NADH from the cytosol to the mitochondrial matrix, and all other conditions are optimal, how many ATP are produced per glucose molecule?"
A) 18
B) 32
C) 36
D) 38
Here's my thought process:
"All other conditions are optimal" is telling me that aerobic respiration will happen (i.e. glycolysis AND the krebs cycle/electron transport chain will happen). Going to assume 3 ATP per NADH and 2 ATP per FADH2 for the sake of this question, since EK said to assume so in the review.
Glycolysis = 2 ATP + 2 NADH = 8 ATP equivalents
Pre-Krebs = 2 NADH = 6 ATP equivalents
Krebs = 2 GTP + 6 NADH + 2 FADH2 = 24 ATP equivalents
Total produced = 38 ATP
Usually, 1 ATP is necessary to transport the NADH produced in Glycolysis into the matrix for the electron transport chain, but according to this question, 2 ATP are needed for each NADH. Thus, I'm going to say that there is a net total of 38 - 2x2 = 34 ATP. This is not one of the answer choices.
I originally wanted to simply say (D), because 38 ATP IS PRODUCED. And then, you use up some ATP to get a lower NET total (normally 36, but in this case, 34).
Here's the explanation EK has:
(B) is correct. The net product of glycolysis for one glucose molecule is 2 ATP and 2 NADH. The additional steps of aerobic respiration produce 34 ATP. This is a net of 36 ATP without accounting for the NADH. Since 2 ATP are used to move each NADH in, this results in the loss of 4 ATP and net product of 32 ATP.
---- I think EK's explanation is wrong. How do the "additional steps of aerobic respiration produce 34 ATP?" Seems to me like the additional steps produce 6+24=30. Also, why do they not factor in the glycolysis NADH into the final calculation of ATP?
Hope someone can give me some clarifications if I'm wrong or agree with me if I'm right. Thanks!
"Assuming that 2 ATP are consumed in moving NADH from the cytosol to the mitochondrial matrix, and all other conditions are optimal, how many ATP are produced per glucose molecule?"
A) 18
B) 32
C) 36
D) 38
Here's my thought process:
"All other conditions are optimal" is telling me that aerobic respiration will happen (i.e. glycolysis AND the krebs cycle/electron transport chain will happen). Going to assume 3 ATP per NADH and 2 ATP per FADH2 for the sake of this question, since EK said to assume so in the review.
Glycolysis = 2 ATP + 2 NADH = 8 ATP equivalents
Pre-Krebs = 2 NADH = 6 ATP equivalents
Krebs = 2 GTP + 6 NADH + 2 FADH2 = 24 ATP equivalents
Total produced = 38 ATP
Usually, 1 ATP is necessary to transport the NADH produced in Glycolysis into the matrix for the electron transport chain, but according to this question, 2 ATP are needed for each NADH. Thus, I'm going to say that there is a net total of 38 - 2x2 = 34 ATP. This is not one of the answer choices.
I originally wanted to simply say (D), because 38 ATP IS PRODUCED. And then, you use up some ATP to get a lower NET total (normally 36, but in this case, 34).
Here's the explanation EK has:
(B) is correct. The net product of glycolysis for one glucose molecule is 2 ATP and 2 NADH. The additional steps of aerobic respiration produce 34 ATP. This is a net of 36 ATP without accounting for the NADH. Since 2 ATP are used to move each NADH in, this results in the loss of 4 ATP and net product of 32 ATP.
---- I think EK's explanation is wrong. How do the "additional steps of aerobic respiration produce 34 ATP?" Seems to me like the additional steps produce 6+24=30. Also, why do they not factor in the glycolysis NADH into the final calculation of ATP?
Hope someone can give me some clarifications if I'm wrong or agree with me if I'm right. Thanks!