This is a pretty out there question... really.
ΔP = -½ρΔ(v²) < 0 (because v_final > v_initial)
- This is proof we lost "pressure" (or kinetic energy that is NOT translational) to translational kinetic energy which does not exert any pressure.
explain this again...?
That statement above says that because the velocity increased, the pressure decreased.
There are two types of kinetic energy that I'm familiar with: 1) the kinetic energy of a molecule associated with its high speed random motion (which is also associated with its pressure and thermal energy), and 2) the translational kinetic energy of a large moving body (i.e. a fluid mass flowing in one direction).
Pressure decreasing will cause a reduction in type 1 kinetic energy.
Since KE = 3/2 RT, KE is proportional to T, so if KE goes down, T must go down.
And, its important to note that you cannot use PV=nRT here because PV=nRT is the "ideal gas" law and we're working with ideal fluids in motion.
What personally gets me is that if you take some water and run it through a very long tubing it will increase in energy. But, I think that's from friction increasing its internal energy, so in the case where there is no friction, I guess that wouldn't happen and we'd get the result I described.