About the ads

  1. Check out PREMED.me!
    Offers FREE service to help premeds manage their applications and MCAT study calendars and identify schools to target.

friction problem

Discussion in 'MCAT Study Question Q&A' started by FRANK1985, Nov 17, 2010.

  1. SDN is a nonprofit organization. Services are made possible through the generous support of SDN members and sponsors. Thank you.
  1. FRANK1985

    FRANK1985

    Joined:
    May 27, 2010
    Messages:
    14
    Status:
    Pre-Medical

    SDN Members don't see this ad. (About Ads)
    Hey guys, help needed, here goes

    A meteor with a mass = 1Kg moving at 20km/s collides with jupiter's atmosphere. the meteor penetrates 100 km into the atmosphere and dsintegrates. What is the average force on the meteor once it enters Jupiter's atmosphere (ignore gravity)?

    a) 2*10^3 N
    b) 4*10^3 N
    c) 8*10^3 N
    d) 2*10^5 N

    thank you
  2. shffl

    shffl

    Joined:
    Sep 20, 2010
    Messages:
    132
  3. FRANK1985

    FRANK1985

    Joined:
    May 27, 2010
    Messages:
    14
    Status:
    Pre-Medical
    that's correct, But i don't get it

    1/2mv^2= F*d
    1/2 * 1 * (20)^2 = F * 100km

    200 = F* 100km
    F= 200/100
    F= 2N

    what am I doing wrong????
  4. ModernAlchemist

    ModernAlchemist Transform and Transcend

    Joined:
    Jan 20, 2008
    Messages:
    1,257
    Location:
    Limbo
    Status:
    Pre-Medical
    SDN 5+ Year Member
    Convert Km to m in both the velocity and the displacement.
  5. FRANK1985

    FRANK1985

    Joined:
    May 27, 2010
    Messages:
    14
    Status:
    Pre-Medical
    DUH!!!! I AM SO RETARDED! thank u so much
  6. ModernAlchemist

    ModernAlchemist Transform and Transcend

    Joined:
    Jan 20, 2008
    Messages:
    1,257
    Location:
    Limbo
    Status:
    Pre-Medical
    SDN 5+ Year Member
    Don't worry about it haha. That has happened to me about 1 million times.
  7. panda2queen

    panda2queen

    Joined:
    Jun 1, 2012
    Messages:
    1
    Status:
    Pre-Medical
    hey I know this was posted a while back, but I am hoping someone can clarify this problem a little for me. I thought that you would use the equation Fdcos(theta) and cos of 0 is just one so then I thought this was set to equal the change in kinetic energy plus the change in potential energy so it would be F*d = delta K + delta U....how come above you just did F*d = delta K...where did the change of potential energy go?

    thanks!
  8. TcDroid4med

    TcDroid4med

    Joined:
    May 15, 2011
    Messages:
    8
    Status:
    Pre-Medical
    SDN 2+ Year Member
    the question says to ignore gravitational force ;)

Share This Page


About the ads