galvanic cell question

[wooki]

a standard galvanic cell utilizes a redox reaction between a 1.0 M aq solution of copper (II) ions and a zinc plate. the reactants are contained in 2 separate vessels, and are bridged only by a conducting wire and a salt bridge. a copper plate as an electrode between the wire and the copper solution. as the reaction proceeds, the copper metal will be continuously deposited onto this electrode, in contrast, the zinc plate serves as both the reducing agent and its own electrode. over time, the zinc electrode will erode away as Zn2+ ions are formed and dissolved into solution.

basically, galvanic cell, anode: zinc and cathode: copper.

question: which of the following will NOT reduce the electric current of the galvanic cell?
a. precipitate out the zinc ions
d. precipitate out the copper ions

the right answer is one of those and those were left from my POE. i don't understand how to eliminate the 2 though

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[Isoprop]

If you take away the zinc ions, the zinc plate will produce more ions as zinc oxidizes into zinc ions. Taking away zinc ions won't do anything.

If you take away copper ions, nothing can be reduced. The copper ions are gaining electrons and plate onto the electrode. But take away the copper ions, and nothing can gain electrons.

 

[Isoprop]

so taking away zinc ions will not reduce the current. but taking away copper ions will.