With regards to halogenation of 2-methylbutane, why doesn't a tertiary radical form after the free radical rips off a proton from one of the terminal methyl groups. I thought a tertiary radical would form (after a carbocation rearrangement) because tertiary radicals are the most stable....
Instead, a primary radical forms and we get 1-chloro-2-methylbutane instead of 2-chloro-2-methylbutane.
Thanks for all of your help.
Instead, a primary radical forms and we get 1-chloro-2-methylbutane instead of 2-chloro-2-methylbutane.
Thanks for all of your help.