Help With SDN 120 Question(s)

[doingit4mykid]

I am unclear about some answers/questions on the 120SDN packet -- please assist if you are able to.

#64
- Why is the answer 1360kcal and not 680kcal?
3.4kcal per gram means 200 grams would provide 3.4*200, right? How would I know offhand that the formula is only for a 12 hour supply and not a 24hr supply? I am guessing that there is a basic fact that I obviously don't know. Please clarify.

Speaking of fluid needs. The RxPrep tells how to calculate fluid needs for someone over 20kg. However, is there a "standard" number for the fluid needs for those under 20kg?

....1 or maybe 2 more to follow....

THANK YOU

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[bbooss]

I am unclear about some answers/questions on the 120SDN packet -- please assist if you are able to.

#64
- Why is the answer 1360kcal and not 680kcal?
3.4kcal per gram means 200 grams would provide 3.4*200, right? How would I know offhand that the formula is only for a 12 hour supply and not a 24hr supply? I am guessing that there is a basic fact that I obviously don't know. Please clarify.


....1 or maybe 2 more to follow....

THANK YOU

The answer based on 80 ml per hr(look at the last line of the formula) so it is 1920 ml in 24 hr. then 200 g in 960 so it is 400 g in that 1920ml. 400g *3.4 kcal is 1360

 

[doingit4mykid]

Bboos - thanks so much for the clarification.
Do you (or anyone else, know the answer to the "fluid needs" question above?

Last SDN120 clarification needed;

#91
I cannot get the correct total osmolarity (milliosmoles/L), because I cannot get the 57.6 milliosmoles for KCL part.
I get the 277.78 milliosmoles for dextrose,
and the 154 milliosmoles for Nacl -
- but I keep getting 80 milliosmoles for KCL!

This is what I did;
1Meq of KCl = 0.0745g, so 40Meq is 2.98g

1 mole is 74.5g, so how many moles is 2.98g --that is 0.04moles

0.04moles/L * 2(no. of particles)*1000 = 80MOsmoles/L

Please tell me where I am going wrong!

I know the SDN120 questions come with answers; however -- I seem to work every problem a different way, so I still don't understand how they got 57.6.

Thanks for taking the time to help.

 

[sally v]

I think they calculated the osmolarity of kcl in mOsmol/720ml?????

From #88, 28.8meq of kcl was administered in 720ml in 15hrs

28.8meq = 2.1456g.

so that the osmolarity =

2.1456 * 2 * 1000 /74.5 = 57.6mOsmol

OR 1 meq of kcl = 2mOsmol
28.8meq of kcl =2 * 28.8
=57.6mOsmol

They calculated the osmolarity of kcl in the 720ml administered so far which i don't think is right since they ve already calculated the osmolarity of dextrose and sodium chloride in 1000ml of infusion. Besides the unit of osmolarity is mOsmol/L

 

[NYPharm99]

Review your answer for question # 89
x mmol/2145.6mg = 1 mmol/74.5mg
x = 28.8mmol
KCl dissociates into 2 parts, therefore there are 2 milliosmoles in each millimole (mmol)
28.8 mmol (answer from #90) multiplied by 2milliosmoles/mmol = 57.6 milliosmoles of KCl

 

[Naplesmark]

FYI.. The 120 questions s/b reviewed and know how to calculate the answer. You can do this just go over the math constantly. You cannot pass with a bad math grade.
Goodluck

 

[NYPharm99]

Agreed. I got a lot of math questions and constant practice gave me the confidence to do them quickly and accurately. The questions take up a lot of time so you can't afford to be bogged down in Math and run out of time.

 

[spharm16]

where can I down load this 120 math question? Thanks

 

[lapharmacienne]

Try this link for the questions

http://forums.studentdoctor.net/showpost.php?p=11078420&postcount=6

Sent from my DROID RAZR HD using Tapatalk 2

 

[molyhelp]

where can I down load this 120 math question? Thanks

File is now uploaded here, please see below this line.....

Good luck and please come back and help others....Thank you very much in advance.

 

[Pharmacygrad3741]

Hi there! I'm having a lot of difficulty with figuring out when to do allegation or use a ratio - such as the problems on the SDN 120 like #12 and, #30, #78. For example #12 I solved it setting up proportional ratios - I set up like:
1) I need 10% which is 10g/100mL = x/1000mL (total IV is 1L)
X= 100g needed
2) if I need 100g, how many mLs of the 70% dextrose will I need so:
70g/100mL = 100g/x
X = 142.9mL needed
--- this is way off from the answer key as they used allegation. However I'm SO confused as to when to set up direct ratios like I did above and when I need allegation. Please help if you can my exam is in 4 days and I'm borderline panic attack

Review your answer for question # 89
x mmol/2145.6mg = 1 mmol/74.5mg
x = 28.8mmol
KCl dissociates into 2 parts, therefore there are 2 milliosmoles in each millimole (mmol)
28.8 mmol (answer from #90) multiplied by 2milliosmoles/mmol = 57.6 milliosmoles of KCl

 

[Pharmacygrad3741]

Anyone get a different answer for #103? I got 15mL

 

[molyhelp]

Anyone get a different answer for #103? I got 15mL

Confirming your answer: I got 15 ml, too.

Reason: I define DOUBLE STRENGTH DOPAMINE as 1600 mg in 500 ml (I presented the reasons supporting DOUBLE STRENGTH DOPAMINE as 1600 in 500 ml in the post at this link:
http://forums.studentdoctor.net/thr...review-for-naplex.745265/page-2#post-15902079
Posted 11-19-2014 at 1:48 A.M.)