I am very possibly completely wrong here, because it's been a long time since I've had physics and I haven't gotten to these concepts in my MCAT review yet. Please take what I'm saying with that in mind, and realize that someone more insightful and well-versed in physics will probably be along shortly to answer, as well.
I would approach this from an energy and inertia standpoint, and you can answer it qualitatively (again, if my understanding is correct, which it may not be). I'm also assuming this to be a frictionless incline. I'll also assume that the hoop and disc are rolling without slipping down the incline and that the hoop and disc each have the same mass.
There are two forms of energy to consider here: rotational kinetic energy and translational kinetic energy. If they're being released from the same incline, the only energy available to pull them down the incline is gravitational potential energy.
Conservation of energy tells us that the gravitational potential energy will be converted into kinetic energy to move the objects down the incline.
For the block, all we have is translational kinetic energy and no rotational kinetic energy to consider. For this case, PE=KE. For the MCAT's purposes, all of the gravitational potential energy is converted to kinetic energy for the block.
The hoop and the disc will each have rotational kinetic energy (rKE) in addition to translational kinetic energy (tPE). In this case, PE=KE + rKE. As such, not all of the gravitational potential energy (GPE) in these cases is converted to translational kinetic energy (the kind that generates the velocity). Given that, we know the block will descend the incline the fastest because all of the GPE is converted into tKE.
Now the question is: of the hoop and the disc, which one will acquire the greatest downward velocity? Consider the equation for rotational kinetic energy: rKE=(IW^2)/2. The difference in inertia between the two will dictate the difference in rotational kinetic energy between the two. Recall that objects with more of their mass near their rotational axis have lower inertia, and objects with more of their mass away from their rotational axis have more inertia (resistance to change in rotation).
From that standpoint, the ring/hoop will have more inertia, and will therefore have more rotational kinetic energy. In other words, more of the GPE will be converted to rPE for the hoop because it takes more energy to get the hoop moving. The disc will have less rPE and will therefore end up with more tPE, which means the hoop will go faster.
In the end, I'd say the final velocities of these three objects would be block > disc > hoop. Again, to stress: this is because the block has no rKE, so all of the initial GPE is converted to tKE. The more rKE an object has, the less energy is converted to tPE.
Again, I could be entirely incorrect here, because it's been a long time since I've had this. But that's what I would say if faced with that passage. In any case, I hope this is helpful.
Good luck!