Number of stereoisomers

[soby10]

I have a bicyclic bridged molecule with two stereogenic centers on the bridge so to get the number of stereoisomers you use 2^n so 4. But bc it's bridged it can't rotate so the true number is 2 due to the lack of diastereomers. Is this the correct reasoning? So whatevers chiral center is on the bridge you subtract 2 diasteromers from every chiral center?

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[FreeMCATTutor]

Instead of carrying around all that logic and reasoning, I much prefer remembering these formulas:

2^n - 2 for bicyclic
2^n - 1 for meso
2^n for everything else