Organic Layer vs Aqueous Layer?

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Hey guys. Can someone please be so kind enough to help clear up my confusion on this topic? I never really went into great detail during our organic chemistry lab. Everywhere I look gives an extremely specific and confusing answer. Also from my understanding, anything non soluble in water goes to the organic layer, so why does ether find itself there? Aren't ether's water soluble? Thanks in advance

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I think the general idea is that something like diethyl ether is not very polar (like just above an alkane) and it is aprotic (no F-H, O-H, N-H) so it will not interact much with the aqueous layer. i.e. an alcohol which contains OH group(s) will be water soluble.
 
When you do an extraction, you're trying to separate different compounds with different functional groups and isolate them. There is the organic layer, which is insoluble in water and initially contains all of your compounds that you will eventually separate. The organic layer also contains a solvent (CH2Cl2 or ether) that is insoluble in water. So the organic layer= Compounds we're trying to separate + insoluble solvent. The compounds we're trying to separate are insoluble because even though their functional groups may have dipoles which make them polar, they usually have large R groups that are made of carbon, thus making the whole thing insoluble in water and masking the solubility of the functional group itself. But, the compounds + the solvent are soluble with each other. You separate (extract) the compounds from the insoluble organic layer by making them charged, i.e. adding acid/base to them to protonate/deprotonate the functional groups. Whether you add acid or base, and the order in which you add each acid or base, will depend on the compounds you have. Here's the rules we need to know (from chad): amines are extracted by HCl (amine gets protonated), carboxylic acids are extracted by NaHCO3 or NaOH (carb acid gets deprotonated), phenols are extracted by NaOH (phenol gets deprotonated). After you add each acid or base, you will form a new aqueous layer that contains the compound you were trying to extract. The compound has now become soluble in water because we added a charge to it (positive or negative). Each time you form a new aqueous layer with a new compound, you can isolate it in a test tube. Ether is not soluble because there's not a strong enough dipole between the O and the C to give the O enough of a partial negative charge that would make it water soluble. This is because there's not a big enough electronegativity difference.

(anyone correct me if I made any mistakes, but I think this is the gist)
 
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When you do an extraction, you're trying to separate different compounds with different functional groups and isolate them. There is the organic layer, which is insoluble in water and initially contains all of your compounds that you will eventually separate. The organic layer also contains a solvent (CH2Cl2 or ether) that is insoluble in water. So the organic layer= Compounds we're trying to separate + insoluble solvent. The compounds we're trying to separate are insoluble because even though their functional groups may have dipoles which make them polar, they usually have large R groups that are made of carbon, thus making the whole thing insoluble in water and masking the solubility of the functional group itself. But, the compounds + the solvent are soluble with each other. You separate (extract) the compounds from the insoluble organic layer by making them charged, i.e. adding acid/base to them to protonate/deprotonate the functional groups. Whether you add acid or base, and the order in which you add each acid or base, will depend on the compounds you have. Here's the rules we need to know (from chad): amines are extracted by HCl (amine gets protonated), carboxylic acids are extracted by NaHCO3 or NaOH (carb acid gets deprotonated), phenols are extracted by NaOH (phenol gets deprotonated). After you add each acid or base, you will form a new aqueous layer that contains the compound you were trying to extract. The compound has now become soluble in water because we added a charge to it (positive or negative). Each time you form a new aqueous layer with a new compound, you can isolate it in a test tube. Ether is not soluble because there's not a strong enough dipole between the O and the C to give the O enough of a partial negative charge that would make it water soluble. This is because there's not a big enough electronegativity difference.

(anyone correct me if I made any mistakes, but I think this is the gist)
Thanks! Yeah I found that video from Chad to be very helpful. Thanks for explaining it. Also thanks everyone else, I will also check out the PDF you linked, JLT
 
Thanks! Yeah I found that video from Chad to be very helpful. Thanks for explaining it. Also thanks everyone else, I will also check out the PDF you linked, JLT
Page 81-83 (with the large chart) is what I'd look at
 
Page 81-83 (with the large chart) is what I'd look at
Ok thanks. Also quick questions

So ethers generally are not soluble in water?
Would diethyl ether have a higher boiling point than chloropentane? The answer says chloropentane boiling point is lower, but I thought ethers were very volatile?
 
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