Thanks for your replies! Let me see if I am understanding this correctly:
Remember the number of carbons in each compound.
-RuBP
(5C) + CO2
(1C)--> one
(TWO) 3-PGA
(3C) (So you will get TWO and not one 3-C compound)
-With 2 ATP from light rxn, becomes two 1,3-biphosphoglycerate
-With 2 NADPH from light rxn, becomes two G3P
Each PGAL will need one ATP and one NADPH to become one G3P. so if you have two PGAL, you will need two each of ATP and NADPH, yes.
-One G3P goes on and helps to form glucose.
(question: G3P is a 3C compound & glucose is a 6C compound, is it not correct to think that all 3C in G3P will form 3 out 6 C of the glucose compound? If I think this way, I predict 2 cycles of Calvin Cycle is needed only to form glucose)
-The other G3P continues on with the Calvin cycle, using ATP to reform RuBP
(question: Is 1ATP sufficient to reform this RuBP? The Barron's book showed that 3 ATP are needed!)
You can't just get rid of one 3-C compound (G3P) and leave one in the cycle because you need to go to RuBP (5C), where will you get that other 2C from? You have to continue the cycle, so every 6 cycles, you will have had 12 G3Ps at this point. Out of this 12, 2 can go to make glucose, while the other 10 G3Ps (10*3=30 carbons) will be able to give you back your 6 RuBPs (6*5=30 carbons). Each reaction that makes RuBP needs one ATP, so you need a total of 6 ATPs here.
In general you can say 6 CO2 + 12 ATP (6 for the PGAL step and 6 for the RuBP step) + 6 NADPH -> glucose
Thanks!! Looking forward to all your replies