Quick Orgo Question

[muddyphud]

A compound has the following 1H NMR spectrum: δ 2.5 ppm (1H, t, J = 3 Hz); 3.1 ppm (1H, s); 4.3 ppm (2H, d, J = 3 Hz). The 1H NMR resonance at 4.3 ppm corresponds to protons that are coupled to how many other protons?

How do you arrive to the answer? I'm confused with no given formula on how to tackle this. Appreciate the help!

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[Cawolf]

The spectrum has no protons in the alkene or aromatic range, so I am assuming they just want a simple answer using the N+1 rule. This should work unless there are diastereotopic protons, which I will assume not if this is an MCAT question.

That peak is a doublet, and the number of peaks (2) is equal to n + 1, with n being the coupled protons. So in this case we can simply say a doublet is made by coupling to one other proton.