Because the saturated cobalt (III) itself already has higher concentration of [OH-], mixing it with the saturated thallium(III), which has lower [OH-], is equivalent to diluting [OH-].
Actually, the mixing itself will also dilute [Co] and [Tl] so you cannot really say anything about TI unless volumes are given, but [Co] will absolutely not precipitate. And that strikes out B, D.
Edit: A and C are both possible.
I don't think whoever wrote that question understood the concept very well.