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I'm sure this is a pretty simple question, but for some reason I just can't quite seem to understand it. Given this equation:
C3H8 + 5O2 --> 4 H20 + 3CO2
the question is if one mole of C3H8 is reacted with 2.5 moles of O2, how many moles of H20 will be produced.
Can I just figure it out by saying well normally 5 moles of O2 along with 1 Mol C3H8 give you 4 H2O's, so if it's still 1 mol of C3H8 but now only 2.5 moles of O2, you'd only get half that amount -- or 2 moles H2O?
Thanks!
C3H8 + 5O2 --> 4 H20 + 3CO2
the question is if one mole of C3H8 is reacted with 2.5 moles of O2, how many moles of H20 will be produced.
Can I just figure it out by saying well normally 5 moles of O2 along with 1 Mol C3H8 give you 4 H2O's, so if it's still 1 mol of C3H8 but now only 2.5 moles of O2, you'd only get half that amount -- or 2 moles H2O?
Thanks!