- Joined
- Jun 25, 2014
- Messages
- 31
- Reaction score
- 3
I'm really struggling with these pressure questions, can anyone please explain?! In book II, example 7.2a:
At a specific depth in a swimming pool, a barometer measures the total pressure to be twice that of atmospheric pressure. if the barometer is now submerged to a depth that is twice its initial depth, by how much does the total pressure increase?
a. increase by 50%
b. increase by 100%
c. increase by 200%
d. increase by 300%
Intuitively I would have put a here, which is correct but when I try to solve it I don't get it.
I was using the equation P1-P2 = rho (y2-y1)g
So i got P1-P2 = rho (2-1) because the barometer is submerged to a depth 2x the initial, I don't get where to go from here and the explanation makes no sense to me, somehow they get 3Patm/2Patm
At a specific depth in a swimming pool, a barometer measures the total pressure to be twice that of atmospheric pressure. if the barometer is now submerged to a depth that is twice its initial depth, by how much does the total pressure increase?
a. increase by 50%
b. increase by 100%
c. increase by 200%
d. increase by 300%
Intuitively I would have put a here, which is correct but when I try to solve it I don't get it.
I was using the equation P1-P2 = rho (y2-y1)g
So i got P1-P2 = rho (2-1) because the barometer is submerged to a depth 2x the initial, I don't get where to go from here and the explanation makes no sense to me, somehow they get 3Patm/2Patm