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"How would the period of a simple pendulum be affected, if the point of suspension were moving vertically upward with an acceleration of g/2 m/s^2?"
A. Period increases
B. Period decreases
C. Period remains the same
D. Cannot be determined
Based on the equation f = 1/2pi (square root of g/L), g is directly proportional to the frequency, thus inversely proportional to the period.
In their explanation, they say that the effective g is = g + g/2.
When I saw this, I was confused by how they described the acceleration. By accelerating upward by g/2, I thought that meant that would result in a net downward force of g/2, therefore, the acceleration would still be downward, but decreased. Therefore, acceleration would decrease, frequency would decrease, and period would increase (A). However, due to their explanation of the g/2 adding to g, B is the correct answer.
Could someone help me out with this? Thanks
A. Period increases
B. Period decreases
C. Period remains the same
D. Cannot be determined
Based on the equation f = 1/2pi (square root of g/L), g is directly proportional to the frequency, thus inversely proportional to the period.
In their explanation, they say that the effective g is = g + g/2.
When I saw this, I was confused by how they described the acceleration. By accelerating upward by g/2, I thought that meant that would result in a net downward force of g/2, therefore, the acceleration would still be downward, but decreased. Therefore, acceleration would decrease, frequency would decrease, and period would increase (A). However, due to their explanation of the g/2 adding to g, B is the correct answer.
Could someone help me out with this? Thanks