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The experimenter titrates the 48 hour old sample with 0.2M NaOH to the endpoint, using 12.4 mL of NaOH. She then back-titrates with 12.4mL 0.2M HCL and determines the pKa of the solution. What is the result of this test?
Given:
48 hour old sample has acetylsalicylic acid (pKa 4.56) and salicylic acid (pKa 2.75)
A. pKa=2.75
B. pKa=4.56
C. pKa= between 2.75 and 4.56
D. Cannot be determined from the information given
Given:
48 hour old sample has acetylsalicylic acid (pKa 4.56) and salicylic acid (pKa 2.75)
A. pKa=2.75
B. pKa=4.56
C. pKa= between 2.75 and 4.56
D. Cannot be determined from the information given