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There is a particular question asking for the expression setup of Ba(OH)2 in order to find the solubility product.
Answer in book: Ksp = [Ba2+][OH-]^2
Shouldn't it be Ksp = [Ba2+][2*OH]^2 The 2 coming from the balanced equation.
BaOH2 --> Ba2+ + 2OH-
Answer in book: Ksp = [Ba2+][OH-]^2
Shouldn't it be Ksp = [Ba2+][2*OH]^2 The 2 coming from the balanced equation.
BaOH2 --> Ba2+ + 2OH-