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In a given medium with fixed boundaries, the longest wavelength will set up a standing wave is 4 m. If waves propagate through the medium at 8 m/s, what is the LOWEST possible frequency associated with a standing wave within this medium?
A. 0.5 Hz
B. 1 Hz
C. 2 Hz
D. 4 Hz
I used f=nv/2L, 8/2(4)=8/8=1Hz and arrived at answer choice B but the explanation says:
The lowest harmonic-or fundamental-frequency, f1, corresponds to the longet harmonic-or fundamental-wavelength, lamda1. In this case, then, we find that f1=v/lamda1=(8 m/s)/ 4m=2 Hz.
I thought for standing waves with fixed ends, we were supposed to use f=nv/2L?
A. 0.5 Hz
B. 1 Hz
C. 2 Hz
D. 4 Hz
I used f=nv/2L, 8/2(4)=8/8=1Hz and arrived at answer choice B but the explanation says:
The lowest harmonic-or fundamental-frequency, f1, corresponds to the longet harmonic-or fundamental-wavelength, lamda1. In this case, then, we find that f1=v/lamda1=(8 m/s)/ 4m=2 Hz.
I thought for standing waves with fixed ends, we were supposed to use f=nv/2L?