Normality (n) ? Can anyone explain?

Smooth Operater · Jul 6, 2005

The barron study guide's definition for normality is "the number of equivalents of solute per liter of solution". What does that mean? Hope someone can clarify this.

Then a example question asks "what is the normality of 2.5 M H2SO4?" and give the answer as..
2 H+ * 2.5 = 5.0 N

Can it also be??
1 SO4 * 2.5 = 2.5 N

thank you so much!

Joeybag · Jul 6, 2005

Smooth Operater said:
The barron study guide's definition for normality is "the number of equivalents of solute per liter of solution". What does that mean? Hope someone can clarify this.

Then a example question asks "what is the normality of 2.5 M H2SO4?" and give the answer as..
2 H+ * 2.5 = 5.0 N

Can it also be??
1 SO4 * 2.5 = 2.5 N

thank you so much!

2.5 M H2SO4 would be 5.0 N H2S04, that is b/c H2S04 is diprotic (2H). Basically: Normality=Molarity * N, here N is 2. Another cases 1 M CA(OH)2 would be normality of 2 (b/c (OH)2))
Most of the time normality and molarity are equal, these diprotic acids and thingsl like calcium hydroxide are sorta exceptions. hope this helps.

Smooth Operater · Jul 6, 2005

Thanks Joey for the explanation.

So basically, Normality = Molarity*N, where N is number of H+ or OH- present in the compounds?

How come you don't take account the SO4 in H2SO4 to calculate normality? Is there a explanation for this?

Thanks! 😍

gatszu · Jul 6, 2005

normality is useful in titration/neutralization reactions. proton/acid is reacted w/base (ex. OH-). so you look at mainly H+ & OH-. SO4-- is not exactly involved in neutralization reactions.

Normality (n) ? Can anyone explain?

Smooth Operater

don't bug "operatEr"!

Joeybag

Senior Member

Smooth Operater

don't bug "operatEr"!

gatszu

Member

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