Q on Top Score G-Chem test #1 Q 56 of 30

This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.

bruinguy083

Full Member
10+ Year Member
5+ Year Member
15+ Year Member
Joined
Jan 10, 2007
Messages
29
Reaction score
0
Points
0
Advertisement - Members don't see this ad
where do they get the concentrations for pcl3 and cl2? this is really confusing and irritating me, argghhh!!!.
 
solution explains it really well.... we are given moles & volume, hence we can figure out molarity (M) = moles/L = 14.250/3 = 4.75 right?

Now the question says only 40% of PCL5 decomposes...which means only 4.75M x 40% = 1.9 M reacted. So we are left with 4.75-1.9 = 2.85M of PCl5.

Since the equation is balance..and the mole ratio is 1:1...we will obtain 1.9 of PCl3 & Cl2
Kc = [PCl3][Cl2]/[PCl5]
= (1.9)(1.9)/(2.85)
= (1.9)^2/(2.85)
 
ahhh, my brain is fried and nothing makes sense. i need a break. thanks for the help!!
 
Top Bottom