Le Chat's on Exothermic Rxns/TPR CBT 3 PS #10

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MedChallenge

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If you have an exothermic reaction, removing excess heat would shift the equilibrium to the products, right? What makes it wrong in the case below? I know A is correct but had to guess between A and D.

In order to maintain the maximum yield of ammonia when raising the temperature of the reaction, scientists should:
Correct Answer A.

maintain N2 and H2 at high pressure.
B.

allow N2 and H2 to expand with the increased kinetic energy.
C.

increase the volume in the reaction chamber to favor the forward reaction.
D.

continuously remove the excess heat produced by the forward reaction.
 
If you have an exothermic reaction, removing excess heat would shift the equilibrium to the products, right? What makes it wrong in the case below? I know A is correct but had to guess between A and D.

In order to maintain the maximum yield of ammonia when raising the temperature of the reaction, scientists should:
Correct Answer A.

maintain N2 and H2 at high pressure.
B.

allow N2 and H2 to expand with the increased kinetic energy.
C.

increase the volume in the reaction chamber to favor the forward reaction.
D.

continuously remove the excess heat produced by the forward reaction.
It looks misleading to me too because if the reaction is exothermic, removing heat from the reactants would shift (or maintain) the equlibrium to the right... I would have been stucked just like you...I want to see what other people on SDN will say about that.
 
If you have an exothermic reaction, removing excess heat would shift the equilibrium to the products, right? What makes it wrong in the case below? I know A is correct but had to guess between A and D.

In order to maintain the maximum yield of ammonia when raising the temperature of the reaction, scientists should:
Correct Answer A.

maintain N2 and H2 at high pressure.
B.

allow N2 and H2 to expand with the increased kinetic energy.
C.

increase the volume in the reaction chamber to favor the forward reaction.
D.

continuously remove the excess heat produced by the forward reaction.

If you look at the balanced equation: N2(g) + 3H2(g) --> 2NH3(g) + heat,

Increasing the temperature will cause ammonia to produce 4 moles of reactants. By maintaining a high pressure, the reactants will be forced to the side with fewer moles of gas. In effect, both of these processes cancel each other out so you might be asking yourself, what's the purpose of doing this at all. Well looking at the kinetics of it, increasing the temperature will increase the rate constant. The reaction happens at a more appreciable rate.
 
If you look at the balanced equation: N2(g) + 3H2(g) --> 2NH3(g) + heat,

Increasing the temperature will cause ammonia to produce 4 moles of reactants. By maintaining a high pressure, the reactants will be forced to the side with fewer moles of gas. In effect, both of these processes cancel each other out so you might be asking yourself, what's the purpose of doing this at all. Well looking at the kinetics of it, increasing the temperature will increase the rate constant. The reaction happens at a more appreciable rate.
I don't get your explanation...they are not increasing the temperature here...OP stated that they are removing heat from the reactants which can be interpreted as decreasing the temperature.
 
I don't get your explanation...they are not increasing the temperature here...OP stated that they are removing heat from the reactants which can be interpreted as decreasing the temperature.

" In order to maintain the maximum yield of ammonia when raising the temperature of the reaction, scientists should: "

Please explain how you could remove heat while increasing the temperature. I'd love to know.
 
First off, heating an exothermic reaction causes an abundance of products (heat is a product). To reestablish equilibrium, heat must be consumed and the reaction must shift to the left. Unfortuantely though, this could get a bit confusing because the shift to the left may or may not result in an increase in pressure. If the pressure increases, there may also be a shift in the forward direction to reduce the moles of gas. If the container were not fixed (meaning the volume could expand), the pressure would not change and there would be no shift in the forward direction. I'm assuming for a locked container, an increase in temperature dominates and that the tendency of the reaction to shift to the right (due to increased pressure via temp increase) is negligible.

Choice D would be true if we're considering how the reaction would respond to the increase in temperature only. The question though is asking how we could increase the percent yield of ammonia NOT how to achieve equilibrium. Raising the temperature (adding more heat) forces the reaction to shift left to use up some of that heat, so more reactants are produced. Even if you somehow heated the reaction and then placed the container in a cool external environment to remove excess heat (via conduction or something), this does not increase the yield of ammonia. Instead heat would be lost faster and equilibrium would be reached sooner.

Choice C is wrong because increasing the volume will decrease the pressure. To reestablish equilibrium, the reaction will shift to the side with more moles of gas. For this question, that would be a shift to the left. This does not increase the yield of ammonia.

Choice B is essentially the issue I brought up earlier regarding the type of container. If the volume of the container could expand, there would be no change in pressure because the kinetic energy supplied by the increase in temperature is being used up to expand the volume of the container and thus cool it down until equilibrium is once again reached. In other words, this change won't shift the reaction in the forward direction (no increase of ammonia).

Choice A is correct. The only way we could produce ammonia by heating up this reaction is if we applied a significant amount of pressure as well. By increasing the overall pressure, there would be a shift in the forward direction to relieve the pressure increase by reducing the moles of gas. Choice D, C, and B result in no net increase in ammonia. By process of elimination, choice A is right.

I would imagine though that the yield still wouldn't be as high since there's both a forward and reverse reaction to consider. However, like Graffiti pointed out, it's probably due to the kinetics of the reaction. Some companies increase production by producing a low yield of ammonia at much quicker rate than a high yield of ammonia that would takes ages.
 
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" In order to maintain the maximum yield of ammonia when raising the temperature of the reaction, scientists should: "

Please explain how you could remove heat while increasing the temperature. I'd love to know.
Sorry...I thought the question was about removing heat...did not see if the question had to do with an increase of temp...Therefore, the question is somewhat simple. An increase of temp in an exothermic would shift the equilibrium to the left...In order to offset that an increase pressure is absolutely necessary. Thus, choice A is the perfect answer.
 
ya pretty good question...

if you think of heat as product in this case increasing temp = more heat, more heat drive reaction backwards to the left therefore you would not have enough ammonia, only way to counterbalance that is to bring excess pressure to force more reactants to react and form more ammonia, since there are more moles of gas on the reactant side increasing pressure will force them to react.

N2(g) + 3H2(g) --> 2NH3(g) + heat,

was this given or did you have to derive it?
 
If you have an exothermic reaction, removing excess heat would shift the equilibrium to the products, right? What makes it wrong in the case below? I know A is correct but had to guess between A and D.

In order to maintain the maximum yield of ammonia when raising the temperature of the reaction, scientists should:
Correct Answer A.

maintain N2 and H2 at high pressure.
B.

allow N2 and H2 to expand with the increased kinetic energy.
C.

increase the volume in the reaction chamber to favor the forward reaction.
D.

continuously remove the excess heat produced by the forward reaction.

This could be completely wrong/ a complete jump off to something else but can't you use PV=nRT.. keeping n and R constant. V= maximum yield of ammonia. So if T is increasing then P has to increase in order to maintain the maximum yield of ammonia
 
If you look at the balanced equation: N2(g) + 3H2(g) --> 2NH3(g) + heat,

Increasing the temperature will cause ammonia to produce 4 moles of reactants. By maintaining a high pressure, the reactants will be forced to the side with fewer moles of gas. In effect, both of these processes cancel each other out so you might be asking yourself, what's the purpose of doing this at all. Well looking at the kinetics of it, increasing the temperature will increase the rate constant. The reaction happens at a more appreciable rate.

First off, heating an exothermic reaction causes an abundance of products (heat is a product). To reestablish equilibrium, heat must be consumed and the reaction must shift to the left. Unfortuantely though, this could get a bit confusing because the shift to the left may or may not result in an increase in pressure. If the pressure increases, there may also be a shift in the forward direction to reduce the moles of gas. If the container were not fixed (meaning the volume could expand), the pressure would not change and there would be no shift in the forward direction. I'm assuming for a locked container, an increase in temperature dominates and that the tendency of the reaction to shift to the right (due to increased pressure via temp increase) is negligible.

Choice D would be true if we're considering how the reaction would respond to the increase in temperature only. The question though is asking how we could increase the percent yield of ammonia NOT how to achieve equilibrium. Raising the temperature (adding more heat) forces the reaction to shift left to use up some of that heat, so more reactants are produced. Even if you somehow heated the reaction and then placed the container in a cool external environment to remove excess heat (via conduction or something), this does not increase the yield of ammonia. Instead heat would be lost faster and equilibrium would be reached sooner.

Choice C is wrong because increasing the volume will decrease the pressure. To reestablish equilibrium, the reaction will shift to the side with more moles of gas. For this question, that would be a shift to the left. This does not increase the yield of ammonia.

Choice B is essentially the issue I brought up earlier regarding the type of container. If the volume of the container could expand, there would be no change in pressure because the kinetic energy supplied by the increase in temperature is being used up to expand the volume of the container and thus cool it down until equilibrium is once again reached. In other words, this change won't shift the reaction in the forward direction (no increase of ammonia).

Choice A is correct. The only way we could produce ammonia by heating up this reaction is if we applied a significant amount of pressure as well. By increasing the overall pressure, there would be a shift in the forward direction to relieve the pressure increase by reducing the moles of gas. Choice D, C, and B result in no net increase in ammonia. By process of elimination, choice A is right.

I would imagine though that the yield still wouldn't be as high since there's both a forward and reverse reaction to consider. However, like Graffiti pointed out, it's probably due to the kinetics of the reaction. Some companies increase production by producing a low yield of ammonia at much quicker rate than a high yield of ammonia that would takes ages.

Great explanations...thanks. Yeah, I'm guessing I must have looked at the question stem quickly, but it probably still would have confused me even if I had seen it. Now with your explanations, though, A makes sense. Thanks to both of you!

ya pretty good question...

if you think of heat as product in this case increasing temp = more heat, more heat drive reaction backwards to the left therefore you would not have enough ammonia, only way to counterbalance that is to bring excess pressure to force more reactants to react and form more ammonia, since there are more moles of gas on the reactant side increasing pressure will force them to react.

N2(g) + 3H2(g) --> 2NH3(g) + heat,

was this given or did you have to derive it?

The equation was given but it didn't explicitly say "+ heat". It did state the delta H = -91.8 kJ/mol.

This could be completely wrong/ a complete jump off to something else but can't you use PV=nRT.. keeping n and R constant. V= maximum yield of ammonia. So if T is increasing then P has to increase in order to maintain the maximum yield of ammonia

Actually, I just thought about it...the moles of gas don't stay constant so it wouldn't be ideal, right?
 
Great explanations...thanks. Yeah, I'm guessing I must have looked at the question stem quickly, but it probably still would have confused me even if I had seen it. Now with your explanations, though, A makes sense. Thanks to both of you!



The equation was given but it didn't explicitly say "+ heat". It did state the delta H = -91.8 kJ/mol.



Actually, I just thought about it...the moles of gas don't stay constant so it wouldn't be ideal, right?

I thought the moles would stay the same because you want to keep the maximum yield and since the maximum yield is the max that is possible it wouldn't change if that makes any sense
 
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