2 Grignard situations

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bchang57

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  1. Pre-Dental
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Situation 1:
HC=CH

1) NaNH2, NH3 --> 2) CH3I ---> 3) CH3MgCl ---> MgCl-C=C-CH3 + CH4
(in ether)

Situation 2:
CH3-CH2-C=N:

1) CH3MgCl ---> 2) H3O+ --> CH3-CH2-C-CH3
||
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The question is, why is it that in Situation 1, where the grignard is reacted with an alkyne, the MgCl attaches to the carbon compound (and not the methyl); whereas in Situation 2, where the grignard is reacted with a nitrile, the METHYL attached to the grignard reacts with the carbon compound to replace the N?
 
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