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2011 DAT Destroyer #46 OCHEM

Discussion in 'DAT Discussions' started by pandalove89, Aug 7, 2011.

  1. pandalove89

    7+ Year Member

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    so the reaction is a double dehydrogenation of 2,3-dibromobutane by using reagents 3NaNH2, NH3 with H2O giving us products 2 butyne.


    I thought it would be E1 since the H2O is polar protic but the answer is E1.


    Why?


    Also is the OCHEM section for destroyer overkill? I'm getting my ass kicked.
     
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  3. PooyaH

    2+ Year Member

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    The answer should be E2. Just memorize the fact that formation of an alkyne is E2 regardless of the solvent.
     
  4. Hope30

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    Another thing I want to add, majority of elimination reaction is E2. If you are in doubt whether it is E1 or E2, choose E2.
     
  5. frances362002

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    It should be E2. In Vollhardt's Organic Chemistry text book, there's a table telling you what reaction will take place. NH2- is a strong base, and the halide is a secondary halide, according to the table, E2 should take place.

    Also Destroyer IS overkill for Ochem. I just took the test yesterday, and the Ochem was quite easy.
     
  6. rmm30

    2+ Year Member

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    I remember that table. It was fantastic and almost foolproof.
     

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