M Moka11 Full Member 10+ Year Member Joined Aug 12, 2011 Messages 222 Reaction score 8 Points 4,571 Jun 5, 2013 #1 Advertisement - Members don't see this ad Nitrobenzene is Chlorinated to yield the following intermediates: etc etc etc.........Which intermediate resonance is the most stable The choices all include Cl at P. Isn't NO2 a M director? Last edited: Jun 5, 2013
Advertisement - Members don't see this ad Nitrobenzene is Chlorinated to yield the following intermediates: etc etc etc.........Which intermediate resonance is the most stable The choices all include Cl at P. Isn't NO2 a M director?
M Moka11 Full Member 10+ Year Member Joined Aug 12, 2011 Messages 222 Reaction score 8 Points 4,571 Jun 5, 2013 #2 Bump. Anyone? Am I missing something? Upvote 0 Downvote
X Xo1991 Full Member 10+ Year Member Joined Aug 17, 2011 Messages 98 Reaction score 0 Points 0 Pre-Dental Jun 5, 2013 #3 mklein said: Bump. Anyone? Am I missing something? Click to expand... It is an m-director, but o and p can still occur (~10% of products) I believe what the question is getting at is how a substituent affects carbocation stability; rather than where the electrophile ends up. Upvote 0 Downvote
mklein said: Bump. Anyone? Am I missing something? Click to expand... It is an m-director, but o and p can still occur (~10% of products) I believe what the question is getting at is how a substituent affects carbocation stability; rather than where the electrophile ends up.
M Moka11 Full Member 10+ Year Member Joined Aug 12, 2011 Messages 222 Reaction score 8 Points 4,571 Jun 5, 2013 #4 Xo1991 said: It is an m-director, but o and p can still occur (~10% of products) I believe what the question is getting at is how a substituent affects carbocation stability; rather than where the electrophile ends up. Click to expand... Ooo I thought it was 100% O/P. Thanks! Upvote 0 Downvote
Xo1991 said: It is an m-director, but o and p can still occur (~10% of products) I believe what the question is getting at is how a substituent affects carbocation stability; rather than where the electrophile ends up. Click to expand... Ooo I thought it was 100% O/P. Thanks!
