A chem question

[myair]

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A 49 gram sample of sulforic acid H2SO4 (98 g/mol) contain how many grams of Oxygen aton?

Thank you

 

[myair]

A 49 gram sample of sulforic acid H2SO4 (98 g/mol) contain how many grams of Oxygen atom?

any body knows??

 

[zuma35]

http://forums.studentdoctor.net/showthread.php?t=575767

 

[myair]

Thank you 🙂

for question 1 yo have to know the concept;
you know we have
(n1)M1V1=(n2)M2V2 n1 and n2 are oxidation, reduction numbers from equation for Ce+4 and Fe+2 when you plug the numbers you will have:
n1(30 X0.1)=n2(0.150 X20)===>
n1=n2 in other hand:
Fe+2=========> Fe+3 + 1e
Ce+4 + 1e========> Ce+3
n1 and n2 can be 2 or 3 the point is must be equal that is fit the answer you gave here.
maybe there is simlpe explanation somebody can help you. 🙂

I don't undrestand the last part.

 

[myair]

So basicaly the ratios must be equal like 1:1 because only one electron is changing or multipling correct?

 

[Danny289]

So basicaly the ratios must be equal like 1:1 because only one electron is changing or multipling correct?

you got it: the ratio must be 1:1 it means same number of electrons for example 2 electrons or 3 or even 4 it can be: 1/1 or 2/2 or 3/3 or even 4/4 and go on. don't confuse yourself. if you have problem for this kind of questions aporoach back way. just plug the the numbers in your answers and find the correct answer. when you are doing this method pay attention: you must have oxidation and reduction in same time in your equation .


if I remeber this question is from ADA sample test am I right?

 

[klutzy1987]

This question is very basic and simple. First calculate the percentage by mass of oxygen in H2SO4. This is equal to 64/98=.653 or 65.3%. Multiply that by 49 to get 32 grams of Oxygen.