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31. the asnwer in back says it's e, all are hardy weinberg conditions. a) is NOT. no isolation = gene flow. The population must be isolated from other populations to meet the hardy equilibrium
176. the correct answer should be c. just look it up on wiki or campbell
gen chem
31. the units are mixed up. 1 L atm = 101 J = .1 kj
24L*4atm=96 L atm = 9600 J = 9.6KJ
163. ClF5. all choices are Clf4 though
OChem
119. neither methylamine nor ether reacts with grignard reagents. if there were only one choice we could pick, methyamine should be the one because it's more basic
31. the asnwer in back says it's e, all are hardy weinberg conditions. a) is NOT. no isolation = gene flow. The population must be isolated from other populations to meet the hardy equilibrium
176. the correct answer should be c. just look it up on wiki or campbell
gen chem
31. the units are mixed up. 1 L atm = 101 J = .1 kj
24L*4atm=96 L atm = 9600 J = 9.6KJ
163. ClF5. all choices are Clf4 though
OChem
119. neither methylamine nor ether reacts with grignard reagents. if there were only one choice we could pick, methyamine should be the one because it's more basic