A pipe with two open ends

[jgalt42]

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I actually got this question right on a practice test. It was asking me to find the wavelength for the third harmonic given the length of the pipe. My question is, why do we assume that the open pipe is N(lamda)/2 = L ? I thought a string with 2 close ends can only assume this equation. Thanks!

 

[chiddler]

I actually got this question right on a practice test. It was asking me to find the wavelength for the third harmonic given the length of the pipe. My question is, why do we assume that the open pipe is N(lamda)/2 = L ? I thought a string with 2 close ends can only assume this equation. Thanks!

Open pipe and and double clamped string are both Lambda = 2L/n. Closed pipe is the 4L variant. Also remember the different n values that they can take.

Not much else to say! These are the appropriate equations. If you're looking for proof, I can't help you.