okay, if the problem is like this (your original post)
What is the value of x if (2(5/x+3))^1/2 = 10 ?
a. 3/7
b. 47/5
c. 5/97
d. 2/5
e. 5/47
then (e) is the answer, not -29/10. thus, kaplan was correct.
(2(5/x+3))= (10/x) + 6, so then
(((10/x)+6) ^(1/2))^2 = 10^2
(10/x) + 6=100
10/x= 100-6
10/x=94
10=94x
10/94= x
5/47 = x answer
10/2= 5
94/2=47
hope this helps. your edit problem is different from the first problem. but your answer was correct for the new problem.
your new problem is this after multiplication
(10/(x+3))^(1/2) = 10
which is not the same as
((10/x) + 6)^(1/2) =10
i think u interpreted the parantheses wrong. just observe carefully. hope this helps