a QR question

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Xavier, Yvonne, and Zelda each try
independently to solve a problem. If
their individual probabilities for success are
1/4,1/2,and 5/8
respectively, what is the probability
that Xavier and Yvonne, but not Zelda,
will solve the problem ?

 

[DDS4tehwin]

1/8?

 

[phraud]

Xavier, Yvonne, and Zelda each try
independently to solve a problem. If
their individual probabilities for success are
1/4,1/2,and 5/8
respectively, what is the probability
that Xavier and Yvonne, but not Zelda,
will solve the problem ?

You multiply (1/4)(1/2)(3/8)

The 3/8 is the probability of Zelda getting the question wrong [1-(5/8) = 3/8].

 

[domonas]

nvm