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[deleted482591]

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[bobeanie95]

I ran into the same problem, does anyone understand the reasoning behind this?

 

[theonlytycrane]

As we add I- (to be oxidized), we start out with the full cell potential of .36V. At the end of the titration, the potential will be 0V. The equivalence point (halfway) will be the point where the full cell potential is cut in half.

 

[bobeanie95]

@theonlytycrane thank you!