AAMC 11 Physics

[MedPR]

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So what I did was a=v^2/r. r=10 (given in the passage). Plug in 10 for r and you get 10a=v^2. You want the acceleration to be as close to gravity as possible, so just set it equal to 10 and you get v^2=100. v=10.

??

 

[MedPR]

bump 🙂

 

[MedPR]

bump again!

 

[HollowSuperet36]

I thought from the passage it stated gravity is felt at the floor of the car and the car decreases its angle with the horizontal plane as it increases in speed. So the faster it goes the more the centrifugal force making the car increase in angle and eventually level with the ground.

Note the question said strongest force of gravity, not a force closest to earths force of gravity.

 

[helpdoc111]

I am still lost! I got it right by assuming that's the speed in which the person would feel the most force, but according to its answer, i think the OP would be right. Can anyone further explain? Thanks

 

[ingramw1202]

So what I did was a=v^2/r. r=10 (given in the passage). Plug in 10 for r and you get 10a=v^2. You want the acceleration to be as close to gravity as possible, so just set it equal to 10 and you get v^2=100. v=10.

??

This question is stupid. If i were to do it, I would also get ten. When the person is at his maximum height in the car, the length of his body is parallel to the horizontal. At this point Fc=mv^(2)/r is directed inwards and Fg=mg is directed downward and the angle between the two is 90 degrees. If the person isn't sliding down, then the sum of the forces acting on the car must be zero. Fc is only x component. Fg is only y component. Square both and add them together (mass cancels) and you get v=10. I have no idea why they say it is at the fastest point. The only explanation I can come up with is that the word gravity, as previously stated, does not mean earth's gravity. Maybe they are meaning the force that keeps the person glued to their seat? Which would be what?