Aamc 11 ps #29

[liveoak]

I guess my question is, if it's energy "transferred" and the final kinetic energy is less than the initial potential energy (due to air resistance)...then why did they do their answer like the following? why not find the kinietic energy at terminal velocity, and make that be the energy transferred?? is it because some of the energy is transferred as *gasp* heat due to air resistance? oh jeez...

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[FutureDoctor503]

The question is asking for the amount of PE transformed which also includes the amount of energy lost due to other factors. If you find the KE using the terminal velociy, you forget to take other factors into account.

 

[liveoak]

The question is asking for the amount of PE transformed which also includes the amount of energy lost due to other factors. If you find the KE using the terminal velociy, you forget to take other factors into account.

Yep. Yep. Got to love it when I try to get cute.

Liveoak, go for the lay-up, you don't need the dunk!

 

[3m31250n]

75 x 10 x 1400 = 75 x 14 plus three zeroes

75 x 10 is 750, so 75 x 14 should be around a grand

a grand plus three zeroes is a mil.

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