Hey,
I really don't understand this question. I know that a faraday is the charge per mole of electron. So, the question stem is saying there is 0.1 C/mole of electron (is that right?)...from here i don't where to go...
Approximately how many moles of Al3+ are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (Note: Assume there is excess Al3+ available and that Al3+ is reduced to Al metal only.)
A) 0.033 mol
A faraday is equal to one mole of electric charge. Because each aluminum ion gains 3 electrons, 0.1 faraday of charge will reduce 0.1/3 moles of aluminum, or 0.033 moles of aluminum.
B) 0.050 mol
C) 0.067 mol
D) 0.10 mol
I really don't understand this question. I know that a faraday is the charge per mole of electron. So, the question stem is saying there is 0.1 C/mole of electron (is that right?)...from here i don't where to go...
Approximately how many moles of Al3+ are reduced when 0.1 faraday of charge passes through a cell during the production of Al? (Note: Assume there is excess Al3+ available and that Al3+ is reduced to Al metal only.)
A) 0.033 mol
A faraday is equal to one mole of electric charge. Because each aluminum ion gains 3 electrons, 0.1 faraday of charge will reduce 0.1/3 moles of aluminum, or 0.033 moles of aluminum.
B) 0.050 mol
C) 0.067 mol
D) 0.10 mol