Since a pulley is involved, shouldn't the work done be 1/2 of the original force, and thus 100J?
You can't change the work done by using a machine. That would violate energy conservation by the work-energy theorem. If you can increase an object's potential energy by the same amount by inputting less work, then potential energy wouldn't be a state function.
So is it only the force, F, that is 1/2 with the pulley, but the work of that force still remains same since that is dependent on the distance or height it moves?
Since a pulley is involved, shouldn't the work done be 1/2 of the original force, and thus 100J?
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The point of any machine (pulley, lever (all 3 classes) or inclined plane) is to accomplish a given amount of work (output) for a given amount of work (input).Since a pulley is involved, shouldn't the work done be 1/2 of the original force, and thus 100J?
View attachment 201849