molality = mols of solvent/mass of solute = mols of H3PO4/mass of water (kg)
assume 1 L of solution = 1000mL
1000mL *1.70g/mL = 1700g of solution
if 85% is H3P04, you have 1700g*0.85 = 1445g H3PO4
1445g H3PO4 / 98g/mol = 14.7 mol of H3PO4
then, we had 15% water in 1L of solution, = 0.15L water = 0.15kg
molality = 14.74mols H3P04 / 0.15kg water = 98 molality
Hm... lol..