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So this question is coming out of TBR Gchem Section 4 Passage IX question 56.
A hydroxide anion is formed when water loses a proton (H+) to another water (known as autoionization). If the concentration of dissociated hydroxide anion (OH-) in distilled water is 1.0 x 10^-6 M, the pH of the solution must be:
A. 7.0, because [H3O+] = [OH-]
B. 7.0, because water always has a pH of 7.0
C. 6.0, because [H3O+] = [OH-]
D. 8.0, because the solution is rich in base (OH-)
The answer is C. I had a little trouble understanding the answer explanation but is it C because the autionization of H2O ( H2O + H2O = OH- + H3O+ ) results in equal concentrations of OH- and H3O+ thus the pOH = 6 and the pH = 6?
A hydroxide anion is formed when water loses a proton (H+) to another water (known as autoionization). If the concentration of dissociated hydroxide anion (OH-) in distilled water is 1.0 x 10^-6 M, the pH of the solution must be:
A. 7.0, because [H3O+] = [OH-]
B. 7.0, because water always has a pH of 7.0
C. 6.0, because [H3O+] = [OH-]
D. 8.0, because the solution is rich in base (OH-)
The answer is C. I had a little trouble understanding the answer explanation but is it C because the autionization of H2O ( H2O + H2O = OH- + H3O+ ) results in equal concentrations of OH- and H3O+ thus the pOH = 6 and the pH = 6?