Acids/Bases

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DeathandTaxes

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I'm having trouble figuring out what the calculations should be.

My work:

You have 0.1 Mol of NaCl, so you must have 0.1 Mol of HCL reacting with 0.1 Mol of NaOH.

Then I used MVi = MVf to calculate the normality.

(0.1 Mol NaOH)(50 ml) = (1000 mL)( X mol NaOH)

This would yield be 5/1000 M of NaOH... which isn't any of the choices.
 
MV=MV is molarity (moles/Liter) times volume in Liters not moles*volume. Because we are solving for molarity we just need to divide .1 moles of NaOH/.05L which equals 2.0 moles/Liter.
Hope that helps.
 

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