ACS Gen chem question; stoichiometry

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sweetcinuhstix

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A mixture containing 9 mole of F2 and 4 mol of S is allowed to react. This equation represents the reaction that takes place: 3F2 + S --> SF6

How many moles of F2 remain after 3 mol of S have reacted?

The answer is supposed to be 1.

I don't understand how to get it, i thought the ratio is 3:1 for F2:S.

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With 3 mol S reacted, 9 mol of F2 will have reacted, so there will be 0 mol F2 remaining, and F2 will be the limiting reactant. It's a typo, and there are a few of them in ACS (I think 4-5).
 
With 3 mol S reacted, 9 mol of F2 will have reacted, so there will be 0 mol F2 remaining, and F2 will be the limiting reactant. It's a typo, and there are a few of them in ACS (I think 4-5).

agree... I hate thes typos...THere are quite alot......🙁
 
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