Aldol Condensation

Started by wooj0313
This forum made possible through the generous support of SDN members, donors, and sponsors. Thank you.
Get help with your application

Use all the free resources available to you from SDN: articles, guides, expert advising, forums discussions, and school research.

wooj0313

Full Member
10+ Year Member
Advertisement - Members don't see this ad
I am now studying for aldol condensation and come up with some questions

1. how do we know if my aldol condensation has the correct stereo-chemistry?

2. how do we tell if aldol product reacts with one equivalent of aldehyde instead of two equivalents of aldehyde ( reaction between ketone and aldehyde)?
 
Maybe I'm understanding Aldol Condensations poorly, or i'm understanding your questions poorly but:

1)An Aldol Condensation is a reaction in which the carbonyl carbon of one carbonyl group attacks the alpha carbon of a second carbonyl group. This can occur over 2 molecules, or just one. This initially creates an alcohol, which (through condensation) is reduced to a double bond.

So, for stereo-chemistry: Carbonyl groups have planar stereo chemistry. You're fine there. As for the 'stereo-chemistry of the double bond, I believe you will get a mixture of both Z and E.

2) I believe you would get a mixture of both, when one solution predominating. Remember: an alpha-beta unsaturated carbonyl will react very readily at the alpha carbon because it is resonance stabilized. I think I could use more information here as well. Hope this helps!
 
Unsaturated beta-alpha carbonyl get 1-4 addition which means nucleophile will attack the beta carbon not the alpha carbon (draw resonance will show you that the beta carbon has a partial positive charge)