To add onto klutzy's response: The reason why the more substituted alkene is lower in energy is due to inductive effects. Since the surrounding alkyl groups are sp3 hybridized there is a dipole from going from the flanking sp3 groups towards the sp2 hybridized carbons located on the double bond. Since sp2 orbitals are lower in energy the neighboring alkyl group will shift as much e-density towards the sp2 hybridized carbon as possible. This helps to lower the energy of the molecule as a whole, so there is less energy contained in the structure, hence releasing less energy when combusted.