Alkyne pi bonds are perpendicular to each other? I thought they were parallel?

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EECStoMed

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Alkyne pi bonds are perpendicular to each other? How is that so? I thought they were parallel? Can someone please clarify? According to EK 1001, #59, alkyne pi bonds are perpendicular to each other.
 
I think you're confused between how these bonds are represented in drawing and how they are physically oriented in space. For example, ethyne is usually noted as HC≡CH but the physical location of the pi bonds is shown (in this crappy drawing):

c2h2.jpg

Notice the electron clouds of the pi bonds are oriented perpendicular to each other.
 
Alkyne pi bonds are perpendicular to each other? How is that so? I thought they were parallel? Can someone please clarify? According to EK 1001, #59, alkyne pi bonds are perpendicular to each other.

Well pi bonds are bonds between p-orbitals on adjacent atoms. The p-orbitals are by definition perpendicular to each other, and therefore the two pi bonds in an alkyne are thus perpendicular as well.

Make sense?
 
Does this mean that in an alkyne, the sigma, and 2 pi bonds are all perpendicular to each other? Like an X, Y, Z plane?
 
Alkyne pi bonds are perpendicular to each other? How is that so? I thought they were parallel? Can someone please clarify? According to EK 1001, #59, alkyne pi bonds are perpendicular to each other.

Alkene pi bonds are parallel, alkyne pi bonds are perpendicular.
 
Just remember the picture of the pi-electrons as 6 balloons all held together at the point. This should help with the visualization.
 
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