Farcus Full Member 15+ Year Member Joined Nov 28, 2007 Messages 829 Reaction score 29 Points 4,641 Location My Bed Pharmacist Jul 30, 2008 #1 Advertisement - Members don't see this ad Ok I think I know why the answer is what it is but can someone just tell me my reasoning is right or wrong. Ok this compound would be aromatic 4n+2, however, the two carbons on the left side of the compound is SP3 hybrid and thus its not aromatic right?
Advertisement - Members don't see this ad Ok I think I know why the answer is what it is but can someone just tell me my reasoning is right or wrong. Ok this compound would be aromatic 4n+2, however, the two carbons on the left side of the compound is SP3 hybrid and thus its not aromatic right?
M murdoc9 Full Member Verified Member 15+ Year Member Joined Jul 15, 2008 Messages 257 Reaction score 55 Points 4,661 Attending Physician Jul 30, 2008 #2 correct. it has to be a completely conjugated cyclic pi system and obey the 4n+2 rule. this compound is non-aromatic. Upvote 0 Downvote
correct. it has to be a completely conjugated cyclic pi system and obey the 4n+2 rule. this compound is non-aromatic.
